My mom and I are having a problem understanding this. I'm gonna post the problem and ask you guys a few questions about it and hopefully you can help me understand it. Thanks 
Here it is:
"Hypothetical gases A and B are both diatomic, which means that molecules of gases A and B are made up of two atoms each. This description might be represented in this way:
gas A = AA = Asubscript2 = diatomic A
gas B = BB = Bsubscript2 = diatomic B
Six grams of AA are required to make three moles of gas A. Therefore the mass of one mole of gas A is 2g.
The mass ratio of B/A = 14/1. This ratio means that the mass of one mole of gaseous B equals 28g (B = 28g).
In a chemical reaction, data shows that three volumes of gas A are needed to use up one volume of gas B, and two volumes of product are made. This reaction can be represented in any of the following ways:
3Asubscript2 +Bsubscript2 -----> 2 units of product
3 AA +BB -----> 2 products
3 volumes +1 volume -----> 2 volumes of product
3 liters +1 liter -----> 2 liters product
3 moles Asubscript2 +1 mole Bsubscript2 -----> 2 moles product"
I actually understood the whole thing until I reached the part where they're showing me all the ways the reaction can be represented. I don't understand why adding 3 liters to 1 liter will give me 2 liters of product and so on. Could someone explain this to me?
And they also gave me this question:
How many grams of product are formed? _____
My answer was 28grams - 6 grams (1 mole Bsubscript2 - 3 moles Asubscript2) which is 22 grams. I came to this conclusion because of the way they seemed to be subtracting the reactants earlier. But the correct answer is 34 grams. Once again, I do not understand how they got it.
Any help would be much appreciated.
Thanks
Here it is:
"Hypothetical gases A and B are both diatomic, which means that molecules of gases A and B are made up of two atoms each. This description might be represented in this way:
gas A = AA = Asubscript2 = diatomic A
gas B = BB = Bsubscript2 = diatomic B
Six grams of AA are required to make three moles of gas A. Therefore the mass of one mole of gas A is 2g.
The mass ratio of B/A = 14/1. This ratio means that the mass of one mole of gaseous B equals 28g (B = 28g).
In a chemical reaction, data shows that three volumes of gas A are needed to use up one volume of gas B, and two volumes of product are made. This reaction can be represented in any of the following ways:
3Asubscript2 +Bsubscript2 -----> 2 units of product
3 AA +BB -----> 2 products
3 volumes +1 volume -----> 2 volumes of product
3 liters +1 liter -----> 2 liters product
3 moles Asubscript2 +1 mole Bsubscript2 -----> 2 moles product"
I actually understood the whole thing until I reached the part where they're showing me all the ways the reaction can be represented. I don't understand why adding 3 liters to 1 liter will give me 2 liters of product and so on. Could someone explain this to me?
And they also gave me this question:
How many grams of product are formed? _____
My answer was 28grams - 6 grams (1 mole Bsubscript2 - 3 moles Asubscript2) which is 22 grams. I came to this conclusion because of the way they seemed to be subtracting the reactants earlier. But the correct answer is 34 grams. Once again, I do not understand how they got it.
Any help would be much appreciated.
Thanks