Recent content by Old Science Guy

revs = meters / (meters/rev) = 80 m / (pi * 1.5 m/rev)

if you had focal length (f) then you could let Di= X and Do= X+55 because image and object are on the same side of the lens and 1/f = 1/Di + 1/Do 1/f = 1/X + 1/(X+55) put in f and solve for X btw for a diverging lens f is negative and Di will be negative, too I guess if you don't have f then...

there are exactly 2.54 cm/in by definition so there are 2.54^3 cm^3 / in^3 then 7.63 in^3 * 16.39 cm^3 / in^3 = 125 cm^3

the gas coming out of the stove is at about 1/4 psi over the atmospheric pressure which is about 15 psi. it's just enough to make sure it flows OUT of the pipes

use the forward v and the d to goal to calculate the time to goal v=d/t then use the t in y = vi*t + 1/2*g*t^2 ( remember g is down so -9.81) finally compare y to 3.0 to get over/under

(P + (n^2*a/v^2) is 3447 by my calculations and P = 1985 do not know what's wrong good luck

this is a physical decomposition replacement looks like A + BX ---> AX + B sometimes the coefficient for water is fractional which would need to be resolved when balancing

draw the vectors add the vectors (E and W consolidate nicely at 20,W) magnitude should just be about 45 net displacement is about 45, 27 degrees W of N

2 NaOH ---> Na20 + H20 mole ratio is 2:1 so it takes (2 mol NaOH / mol H20) use as a conversion factor solving 30 mol H2O * 2 mol NaOH/mol H2O =........ .........60 mol NaOH