if you had focal length (f)
then you could let Di= X and Do= X+55 because image and object are on the same side of the lens
and
1/f = 1/Di + 1/Do
1/f = 1/X + 1/(X+55)
put in f and solve for X
btw for a diverging lens f is negative and Di will be negative, too
I guess if you don't have f
then you could solve for X in terms of f