A active open programming New member Jun 13, 2009 #2 I don't understand this question. Are you excluding the instructions? (1/5)^(-6) = 15625 (5/1)^6 = 15625, perhaps the point is that it is easier to enter a positive exponent into a calculator than a negative exponent?
I don't understand this question. Are you excluding the instructions? (1/5)^(-6) = 15625 (5/1)^6 = 15625, perhaps the point is that it is easier to enter a positive exponent into a calculator than a negative exponent?
K KelsieBoo Guest Jun 13, 2009 #3 i think you want this in logarithmic form? log(15625) 1/5 = -6 (base 15625; i can't write it small...)
i think you want this in logarithmic form? log(15625) 1/5 = -6 (base 15625; i can't write it small...)
