J jolie New member Jul 13, 2009 #1 write an equation of the line that passes trough the two given points. write the result in slope- intercept form.
write an equation of the line that passes trough the two given points. write the result in slope- intercept form.
B B.B. New member Jul 13, 2009 #2 slope first (y1-y2)/(x1-x2) 2+4/-2-2 = 6/-4 = -3/2 y-y1=m(x-x1) y+4=(-3/2)(x-2) y+4=-3x/2 +3 y=-3x/2-1
slope first (y1-y2)/(x1-x2) 2+4/-2-2 = 6/-4 = -3/2 y-y1=m(x-x1) y+4=(-3/2)(x-2) y+4=-3x/2 +3 y=-3x/2-1
V veerendra v Guest Jul 13, 2009 #3 eqn is (y-y1)=m(x-x1) m=(y2-y1)/(x2-x1) m=-3/2 eqn (y-2)=-3/2(x+2) 3x+2y=-2 slope interrcet form is x/(-2/3)+y/(-1)=1
eqn is (y-y1)=m(x-x1) m=(y2-y1)/(x2-x1) m=-3/2 eqn (y-2)=-3/2(x+2) 3x+2y=-2 slope interrcet form is x/(-2/3)+y/(-1)=1
