a) Sb3+ forms a precipitate
b) antimony (III) hydroxide dissolves when more OH- is added
c) Sb3+ forms a complex ion
so I think the answers are...
a) Sb3+ + 3OH- --> Sb(OH)3
b) Sb(OH)3 + OH- --> Sb(OH)4 -
c) Sb3+ + 4OH- --> Sb(OH)4 -
but I need help explaining why each answer is the answer. Also I'm not sure if the equations are at equilibrium (double arrow) or go to completion (single arrow) and what the states are for each.
b) antimony (III) hydroxide dissolves when more OH- is added
c) Sb3+ forms a complex ion
so I think the answers are...
a) Sb3+ + 3OH- --> Sb(OH)3
b) Sb(OH)3 + OH- --> Sb(OH)4 -
c) Sb3+ + 4OH- --> Sb(OH)4 -
but I need help explaining why each answer is the answer. Also I'm not sure if the equations are at equilibrium (double arrow) or go to completion (single arrow) and what the states are for each.