write a net ionic equation for the reaction with OH- by which...?

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a) Sb3+ forms a precipitate
b) antimony (III) hydroxide dissolves when more OH- is added
c) Sb3+ forms a complex ion

so I think the answers are...

a) Sb3+ + 3OH- --> Sb(OH)3
b) Sb(OH)3 + OH- --> Sb(OH)4 -
c) Sb3+ + 4OH- --> Sb(OH)4 -

but I need help explaining why each answer is the answer. Also I'm not sure if the equations are at equilibrium (double arrow) or go to completion (single arrow) and what the states are for each.
 
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