G galluer New member Apr 22, 2009 #1 Conservation of Angular Momentum. (Radius of stretching ) ^2 x Angular Frequency = const.
M Marlo New member Apr 22, 2009 #2 horizontal bar wit? Why is the rotational inertia greater for a gymnast when she swings by her hands from a horizontal bar with her body fully extended than when she executes a somersault with her body fully extended?
horizontal bar wit? Why is the rotational inertia greater for a gymnast when she swings by her hands from a horizontal bar with her body fully extended than when she executes a somersault with her body fully extended?
G galluer New member Apr 22, 2009 #3 Conservation of Angular Momentum. (Radius of stretching ) ^2 x Angular Frequency = const.
G Gaurav Guest Apr 22, 2009 #4 Rotational Inertia = 1/2 M x r x r (half - M r squared) So If gymnast is extending her hands, the r (radius of rotation) increases which increases the inertia
Rotational Inertia = 1/2 M x r x r (half - M r squared) So If gymnast is extending her hands, the r (radius of rotation) increases which increases the inertia
G Gaurav Guest Apr 22, 2009 #5 Rotational Inertia = 1/2 M x r x r (half - M r squared) So If gymnast is extending her hands, the r (radius of rotation) increases which increases the inertia
Rotational Inertia = 1/2 M x r x r (half - M r squared) So If gymnast is extending her hands, the r (radius of rotation) increases which increases the inertia
