N
Nick McKay
Guest
Cylindrical, cardboard postal tube sare made with the restriction that the sum of the length and the circular circumferencer are 120cm. What should the dimensions be for maxiumum volume.
Sooo,
2pi*R + L(length) = 120
L = 120-pi2R
Volume = piR^2 * (120-pi2R)
Deriving this and I only get a minimum, r = 0,
Any help is much appreciatd, thank you!
Sooo,
2pi*R + L(length) = 120
L = 120-pi2R
Volume = piR^2 * (120-pi2R)
Deriving this and I only get a minimum, r = 0,
Any help is much appreciatd, thank you!