K Kelly New member Jul 10, 2009 #1 A simple pendulum has mass 1.42 kg and length 0.750 m. (a) What is the period of the pendulum near the surface of Earth? (b) If the same mass is attached to a spring, what spring constant would result in the period of motion found in part (a)?
A simple pendulum has mass 1.42 kg and length 0.750 m. (a) What is the period of the pendulum near the surface of Earth? (b) If the same mass is attached to a spring, what spring constant would result in the period of motion found in part (a)?
J Jacy New member Jul 11, 2009 #2 a) T = 2(pi)sqrt{ L/g} = 2(pi) sqrt{0.75/9.8} = 1.74 s b) T = 2(pi)sqrt{m/k} = 2(pi)sqrt{1.42/k} = 1.74 k = 1.42 / [(1.74/2(pi))^2] = 18.5 N/m
a) T = 2(pi)sqrt{ L/g} = 2(pi) sqrt{0.75/9.8} = 1.74 s b) T = 2(pi)sqrt{m/k} = 2(pi)sqrt{1.42/k} = 1.74 k = 1.42 / [(1.74/2(pi))^2] = 18.5 N/m
