C
Classicalmusicalfan
Guest
Hi everyone,
What does this become when you evaluate it with the limit t to infinity?
ln [ {e^(at) - b} / e^(at) ] , where a and b are constants?
Is it possible to divide infinity by infinity? Or do I need to split up the log into :
ln (e^at - b) - ln (e^at) = ln (e^at - b) - at
= ln (infinity) - infinity
= ?
Thanks!
What does this become when you evaluate it with the limit t to infinity?
ln [ {e^(at) - b} / e^(at) ] , where a and b are constants?
Is it possible to divide infinity by infinity? Or do I need to split up the log into :
ln (e^at - b) - ln (e^at) = ln (e^at - b) - at
= ln (infinity) - infinity
= ?
Thanks!