2.13 M solution means 2.13 moles of KBr per liter of water.
also, 670 grams of water is 0.670 liters
so you multiply the two numbers to get the moles of KBr needed
2.13 M x 0.670 L = 1.4271 moles KBr
then times by molar mass
1.4271 x (80g/mol + 39g/mol_ = 169.8 grams
so you need
169.8 grams KBr