...in that two tables? Here is the code, in this following code I have coded to select * from table inquiry where lastname matches the search.
I want to select from two tables customer table and inquiry table and i want to display the search result in which last name matches in both table. Can you tell me what to add in this code for that?
<?php
// Get the search variable from URL
$var = @$_GET['q'] ;
$trimmed = trim($var); //trim whitespace from the stored variable
// rows to return
$limit=10;
// check for an empty string and display a message.
if ($trimmed == "")
{
echo "<p>Please enter a search...</p>";
exit;
}
// check for a search parameter
if (!isset($var))
{
echo "<p>We dont seem to have a search parameter!</p>";
exit;
}
//connect to your database ** EDIT REQUIRED HERE **
mysql_connect("localhost","root","password"); //(host, username, password)
//specify database ** EDIT REQUIRED HERE **
mysql_select_db("crmdb") or die("Unable to select database"); //select which database we're using
// Build SQL Query
$query = "select * from inquiry WHERE LastName like \"%$trimmed%\"
order by LastName";
// EDIT HERE and specify your table and field names for the SQL query
$numresults=mysql_query($query);
$numrows=mysql_num_rows($numresults);
// If we have no results, offer a google search as an alternative
if ($numrows == 0)
{
echo "<h4>Results</h4>";
echo "<p>Sorry, your search: "" . $trimmed . "" returned zero results</p>";
}
// next determine if s has been passed to script, if not use 0
if (empty($s)) {
$s=0;
}
// get results
$query .= " limit $s,$limit";
$result = mysql_query($query) or die("Couldn't execute query");
// display what the person searched for
echo "<p>You searched for: "" . $var . ""</p>";
// begin to show results set
echo "Results";
$count = 1 + $s ;
echo "<table width=200 border=1>
<tr>
<th>ID</th>
<th>Date</th>
<th>Job Type</th>
<th>Commodity</th>
<th>Volume</th>
<th>Inquiry Mode</th>
<th>Transportation</th>
</tr>";
while($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['id'] . "</td>";
echo "<td>" . $row['date'] . "</td>";
echo "<td>" . $row['jobtype'] . "</td>";
echo "<td>" . $row['commodity'] . "</td>";
echo "<td>" . $row['volume'] . "</td>";
echo "<td>" . $row['inquirymode'] . "</td>";
echo "<td>" . $row['transportation'] . "</td>";
echo "</tr>";
}
echo "</table>";
$currPage = (($s/$limit) + 1);
//break before paging
echo "<br />";
// next we need to do the links to other results
if ($s>=1) { // bypass PREV link if s is 0
$prevs=($s-$limit);
print "*<a href=\"$PHP_SELF?s=$prevs&q=$var\"><<
Prev 10</a> *";
}
// calculate number of pages needing links
$pages=intval($numrows/$limit);
// $pages now contains int of pages needed unless there is a remainder from division
if ($numrows%$limit) {
// has remainder so add one page
$pages++;
}
// check to see if last page
if (!((($s+$limit)/$limit)==$pages) && $pages!=1) {
// not last page so give NEXT link
$news=$s+$limit;
echo "*<a href=\"$PHP_SELF?s=$news&q=$var\">Next 10 >></a>";
}
$a = $s + ($limit) ;
if ($a > $numrows) { $a = $numrows ; }
$b = $s + 1 ;
echo "<p>Showing results $b to $a of $numrows</p>";
?>
I want to select from two tables customer table and inquiry table and i want to display the search result in which last name matches in both table. Can you tell me what to add in this code for that?
<?php
// Get the search variable from URL
$var = @$_GET['q'] ;
$trimmed = trim($var); //trim whitespace from the stored variable
// rows to return
$limit=10;
// check for an empty string and display a message.
if ($trimmed == "")
{
echo "<p>Please enter a search...</p>";
exit;
}
// check for a search parameter
if (!isset($var))
{
echo "<p>We dont seem to have a search parameter!</p>";
exit;
}
//connect to your database ** EDIT REQUIRED HERE **
mysql_connect("localhost","root","password"); //(host, username, password)
//specify database ** EDIT REQUIRED HERE **
mysql_select_db("crmdb") or die("Unable to select database"); //select which database we're using
// Build SQL Query
$query = "select * from inquiry WHERE LastName like \"%$trimmed%\"
order by LastName";
// EDIT HERE and specify your table and field names for the SQL query
$numresults=mysql_query($query);
$numrows=mysql_num_rows($numresults);
// If we have no results, offer a google search as an alternative
if ($numrows == 0)
{
echo "<h4>Results</h4>";
echo "<p>Sorry, your search: "" . $trimmed . "" returned zero results</p>";
}
// next determine if s has been passed to script, if not use 0
if (empty($s)) {
$s=0;
}
// get results
$query .= " limit $s,$limit";
$result = mysql_query($query) or die("Couldn't execute query");
// display what the person searched for
echo "<p>You searched for: "" . $var . ""</p>";
// begin to show results set
echo "Results";
$count = 1 + $s ;
echo "<table width=200 border=1>
<tr>
<th>ID</th>
<th>Date</th>
<th>Job Type</th>
<th>Commodity</th>
<th>Volume</th>
<th>Inquiry Mode</th>
<th>Transportation</th>
</tr>";
while($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['id'] . "</td>";
echo "<td>" . $row['date'] . "</td>";
echo "<td>" . $row['jobtype'] . "</td>";
echo "<td>" . $row['commodity'] . "</td>";
echo "<td>" . $row['volume'] . "</td>";
echo "<td>" . $row['inquirymode'] . "</td>";
echo "<td>" . $row['transportation'] . "</td>";
echo "</tr>";
}
echo "</table>";
$currPage = (($s/$limit) + 1);
//break before paging
echo "<br />";
// next we need to do the links to other results
if ($s>=1) { // bypass PREV link if s is 0
$prevs=($s-$limit);
print "*<a href=\"$PHP_SELF?s=$prevs&q=$var\"><<
Prev 10</a> *";
}
// calculate number of pages needing links
$pages=intval($numrows/$limit);
// $pages now contains int of pages needed unless there is a remainder from division
if ($numrows%$limit) {
// has remainder so add one page
$pages++;
}
// check to see if last page
if (!((($s+$limit)/$limit)==$pages) && $pages!=1) {
// not last page so give NEXT link
$news=$s+$limit;
echo "*<a href=\"$PHP_SELF?s=$news&q=$var\">Next 10 >></a>";
}
$a = $s + ($limit) ;
if ($a > $numrows) { $a = $numrows ; }
$b = $s + 1 ;
echo "<p>Showing results $b to $a of $numrows</p>";
?>