Tricky Riddle that i need to solve!?

B

Bryce

New member
Three men and a monkey live in a treehouse on an island. The men find a nice ripe bunch of bananas but it takes them all day to get up the tree and bring them down. So they decide to go to sleep and divide up the bananas in the morning.

During the night the first man wakes up while the others sleep, looks at the bananas, and decides to take his 1/3 of the bunch. Since the bunch didn't divide evenly he gave the extra banana to the monkey. After he fell asleep the second man woke up in the same way and took his third, giving the extra banana to the monkey. Finally the third man woke up and did the same, taking a third of the bananas in the bunch and since it didn't divide evenly into three's he gave the extra banana to the monkey.

The next morning the men woke up and divided up what was left into three piles, giving the extra banana to the monkey.

What is the least number of bananas that could be in this bunch?

Try and come up with a formula!
 
edit: okay i got it


Least amount? 19 i think

First guy takes 6 and an extra 1 for monkey, 12 left.
Second guy takes 4 and an extra 1 for monkey, 7 left.
Third guy takes 2 and an extra 1 for monkey, 4 left.
They wake up, take 1 banana each, and give the last to the monkey.

N= number of bananas in bunch
X= number of bananas taken by human

Formula written sorta funny... (N minus 1) divided by 3 equals X number of bananas to take.

3 to monkey
maybe
 
edit: okay i got it


Least amount? 19 i think

First guy takes 6 and an extra 1 for monkey, 12 left.
Second guy takes 4 and an extra 1 for monkey, 7 left.
Third guy takes 2 and an extra 1 for monkey, 4 left.
They wake up, take 1 banana each, and give the last to the monkey.

N= number of bananas in bunch
X= number of bananas taken by human

Formula written sorta funny... (N minus 1) divided by 3 equals X number of bananas to take.

3 to monkey
maybe
 
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