brianlamhang
New member
mL of 0.01205 M EDTA.? Titration of Ca2+ and Mg2+ in a 50.00 mL sample of hard water required 23.65 mL of 0.01205 M EDTA. A second 50.00 mL aliquot was made strongly basic with NaOH to precipitate Mg2+ as Mg(OH)2(s). The supernatant liquid was titrated with 14.53 mL of the EDTA solution.
a) Assuming that water hardness is expressed in ppm CaCO3, and that the ppm of CaCO3 is assumed to be equal to the total ppm of Ca2+ and Mg2+, express the water hardness as ppm of CaCO3.
b) Calculate the concentration in ppm of CaCO3 in the sample.
c) Calculate the concentration in ppm of MgCO3 in the sample.
a) Assuming that water hardness is expressed in ppm CaCO3, and that the ppm of CaCO3 is assumed to be equal to the total ppm of Ca2+ and Mg2+, express the water hardness as ppm of CaCO3.
b) Calculate the concentration in ppm of CaCO3 in the sample.
c) Calculate the concentration in ppm of MgCO3 in the sample.