so for 2 moles of CO -482kJ of heat is released
for 12.0 g we must find the moles of how much CO is in 12.0g
m = 12.0
M = CO = 12.01 + 16 =28.01 g/mol
n = 0.428mols
so for 2mols -482kJ is released...
make a ration 2/482 = 0.428/x
x = -103.24
so approx. -103kJ of heat is released