S steve_geo1 New member Sep 10, 2009 #1 2Al + 3Br2 ===> Al2Br6 2.43molAl2Br6 x 2molAl/1molAl2Br6 = 4.86 moles Al
1 1337 New member Sep 10, 2009 #2 Al + Br2 yields Al2Br6 (unbalanced) how many moles of Al are needed to form 2.43 mol of Al2Br6 please exlpain
Al + Br2 yields Al2Br6 (unbalanced) how many moles of Al are needed to form 2.43 mol of Al2Br6 please exlpain
S steve_geo1 New member Sep 10, 2009 #3 2Al + 3Br2 ===> Al2Br6 2.43molAl2Br6 x 2molAl/1molAl2Br6 = 4.86 moles Al
D DrGaellon New member Sep 10, 2009 #4 First balance the equation: 2Al + 3Br2 = Al2Br6 From this, you can see that you need 2 mol of Al to make 1 mol of Al2Br6, so you need 4.86 mol of Al to answer the question.
First balance the equation: 2Al + 3Br2 = Al2Br6 From this, you can see that you need 2 mol of Al to make 1 mol of Al2Br6, so you need 4.86 mol of Al to answer the question.
