R
Rogi P
Guest
Consider the solid S described below.
The base of S is the region enclosed by the parabola y = 1 - x2 and the x-axis. Cross-sections perpendicular to the y-axis are squares.
Find the volume V of this solid.
ok so i keep getting 8/3 as an answer but when i enter it it keeps coming up as wrong.
i solved it in terms of x so that x=(1-y^2)^1/2
the area of the square would be 2x or 2(1-y^2)^1/2)
square 2x to get the area and you get 4(1-y^2)
to get volume you multiply by dy
to get the sum of the volumes of all teh squares take the integral of this from zero to one and i keep getting 8/3
what am i doing wrong?
The base of S is the region enclosed by the parabola y = 1 - x2 and the x-axis. Cross-sections perpendicular to the y-axis are squares.
Find the volume V of this solid.
ok so i keep getting 8/3 as an answer but when i enter it it keeps coming up as wrong.
i solved it in terms of x so that x=(1-y^2)^1/2
the area of the square would be 2x or 2(1-y^2)^1/2)
square 2x to get the area and you get 4(1-y^2)
to get volume you multiply by dy
to get the sum of the volumes of all teh squares take the integral of this from zero to one and i keep getting 8/3
what am i doing wrong?