Some kids try to hit a soda can with a stone tied to the end of a string. One kid

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214 Metroline

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All the information about the swing is irrelevant because it does not affect the vertical motion of the rock.

Vertical motion of the rock is

s = ½gt²
t = √(2s/g)
t = 0.535s

This obviously assumes the can is on the floor.
 
swings the rock at a height? of 1.40m above the ground in a horizontal circle. It takes 1.26 s for the rock to complete one revolution at a constant speed of 4.00 m/s. When the kid releases the string, the rock flies forward at a horizontal velocity.

How long does it take for the rock to hit the can at the instant it is released from the string?

Help ! the answer is .534s but How do I approach this ?
 
we need to know how far away the can is , in order to know the distance the rock has to travel. Then divide that by the velocity.
 
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