coairrob777
New member
4x - 2x^2
I'm pretty sure I have the answer already, but I just want to be absolutely sure. What I did was the integral from 0 to 2, 2pi (4-x)(4x-2x^2) dx. Is that the correct way? Like I said, I just wanted to be sure this was correct.
Forgot to mention, it's the region bounded by the curve, x, and y axis.
I'm pretty sure I have the answer already, but I just want to be absolutely sure. What I did was the integral from 0 to 2, 2pi (4-x)(4x-2x^2) dx. Is that the correct way? Like I said, I just wanted to be sure this was correct.
Forgot to mention, it's the region bounded by the curve, x, and y axis.