projectile motion question...baseball home run?

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physicsdude1000

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A baseball player hits a home run- using this data, calculate the initial velocity with which he hit the ball.

Xo(initial horizontal distance)=0
X (horizontal distance traveled)= 100 m
Yo (initial vertical distance aka height of batters chest)= 1.5 m
y (final vertical distance= 17m
theta= 40 degrees

calculate initial velocity (Vo)
 
Assume acceleration in y is due to gravity -9.8.

So 17-1.5 = -.5(9.8)t^2
solve for t = 1.77s

X= Xo +Vxi*1.77s
100 = 0 +Vxi * 1.77s

Vxi = 56.5 m/s this is velocity in the x direction.

Vo = 56.5/cos(40)

Vo = 73.75 m/s

This seems really fast, i dont know if it is correct or not but i hope it helps
 
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