Probability: Given 3 components' probability of passing inspection, chance that two

Kevin

New member
will pass...? I have three components, A, B, and C. Probability of A passing inspection P(A) is 0.95.
P(B) is 0.98.
P(C) is 0.99.

What is the probability that only two components will pass inspection?

I know the answer is 0.07663. How do you figure it out though?
(please describe how to solve)
 
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