C c c New member Jan 9, 2010 #1 sin(π/2 - θ) is equal to cos so, Cotθ/cosθ Re-write it as: (Cosθ/Sinθ)/Cosθ multiply it by cosθ top and bottom and you get: 1/sinθ = cscθ
sin(π/2 - θ) is equal to cos so, Cotθ/cosθ Re-write it as: (Cosθ/Sinθ)/Cosθ multiply it by cosθ top and bottom and you get: 1/sinθ = cscθ
C Charlene L Guest Jan 9, 2010 #2 What does the following expression simplify to? cotθ / sin(π/2 - θ)
A Admir New member Jan 9, 2010 #3 CC was right, until the part with the multiplying. you can't multiply, because it wasn't an equation (Cosθ/Sinθ)/Cosθ = 1/Sinθ
CC was right, until the part with the multiplying. you can't multiply, because it wasn't an equation (Cosθ/Sinθ)/Cosθ = 1/Sinθ
C c c New member Jan 9, 2010 #4 sin(π/2 - θ) is equal to cos so, Cotθ/cosθ Re-write it as: (Cosθ/Sinθ)/Cosθ multiply it by cosθ top and bottom and you get: 1/sinθ = cscθ
sin(π/2 - θ) is equal to cos so, Cotθ/cosθ Re-write it as: (Cosθ/Sinθ)/Cosθ multiply it by cosθ top and bottom and you get: 1/sinθ = cscθ
