Imagine comparing the mean of 9 measurements to a known value, and finding difference =0.5s = 1.5sm The probability that an unbiased method would give such an extreme difference from the ‘true’ mean?? is about 15%.
Imagine comparing the mean of 9 measurements to a known value, and finding difference =0.25s = 0.75sm The probability that an unbiased method would give such an extreme difference from the ‘true’ mean ??is about 50%.
i am really confused how they r finding P .. for #1 is 15 and #2 is 50% i tired everything to solve this .. but i still dunknow how to solve may i have some help plzzzzzzzzzzzzz
Imagine comparing the mean of 9 measurements to a known value, and finding difference =0.25s = 0.75sm The probability that an unbiased method would give such an extreme difference from the ‘true’ mean ??is about 50%.
i am really confused how they r finding P .. for #1 is 15 and #2 is 50% i tired everything to solve this .. but i still dunknow how to solve may i have some help plzzzzzzzzzzzzz