please help bout this problem about gauss's law????best answer gets 10 points?

E

Eden

New member
a.A closed surface encloses a net charge of -3.60µC. What is the net electric flux through the surface?
b.The electric flux through a closed surface is found to be 780 N.m2/C. What quantity of charge is enclosed by the surface?
c.The closed surface in part (b) is a cube with sides of length 2.50 cm. From the information given in part (b), is it possible to tell where within the cube the charge is located? Why?
 
a) By Gauss's theorem
the flux through the closed surface = φ = q/εo = -3.6 x 10^-6/8.9 x 10^-12 = 4x10^5 N.m^2/C

b) q = εo φ = 8.9x10^-12 x 780 = 0.00694 x10^-6 C = 0.007 μC


c) The flux through the surface does not depend on the position of the charge within the surface. It depends on only the total charge enclosed. Hence it is not possible to locate the position of the charge.
 
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