I really don't understand how to do this question:
A particle in an eruption column is held in suspension by gas with a speed
of 30m per second, such that its total rise speed is 5m per second. The frictional force which the gas exerts on the particle is given by fF = 0.78*pi*r^2*u^2, where u is the
relative speed of the particle in the gas and r is its radius. The weight of the
particle is given by wp = (4/3)*pi*r^3*Ppg, where Pp = 2000 kg per cubic meter is the density of the particle. Determine its radius.
I have no clue how to do this, any help would be greatly appreciated
A particle in an eruption column is held in suspension by gas with a speed
of 30m per second, such that its total rise speed is 5m per second. The frictional force which the gas exerts on the particle is given by fF = 0.78*pi*r^2*u^2, where u is the
relative speed of the particle in the gas and r is its radius. The weight of the
particle is given by wp = (4/3)*pi*r^3*Ppg, where Pp = 2000 kg per cubic meter is the density of the particle. Determine its radius.
I have no clue how to do this, any help would be greatly appreciated