A particle having charge 2.5uc and mass m = 0.0150 kg is connected to a string that is L = 2.30 m long and is tied to the pivot point P. The particle, string, and pivot point all lie on a horizontal table. The particle is released from rest when the string makes an angle with a uniform electric field of magnitude E = 270 V/m. Determine the speed of the particle when the string is parallel to the electric field.
i tried this: v = sq rt[(2*q*E*L(1-cos(theta))/m)] and got .322, but i am told this is incorrect. any help would be greatly appreciated!
i tried this: v = sq rt[(2*q*E*L(1-cos(theta))/m)] and got .322, but i am told this is incorrect. any help would be greatly appreciated!