T
tan_alec
Guest
I can actually solve it through reasoning, but I can't figure it out via equations. Here's the question:
"A stone is vertically thrown upward from the edge of a cliff 65m high with a speed of 10.0 m/s. It reached the bottom 4.8 seconds later and hit the bottom of the cliff with a speed of 37 m/s. What total distance did it travel?"
I used these two equations (given y= distance, yi= initial distance, vi= initial velocity):
a. y=yi+vi(t)+1/2g(t^2)
b. v^2=vi^2+2a(y-yi)
And did not get the correct answer (which was 75 m). Can anybody give me the solution, or at the very least, a hint or correction? Thanks in advance.
P.S. I made sure that my calculations were correct in their mathematical nature.
"A stone is vertically thrown upward from the edge of a cliff 65m high with a speed of 10.0 m/s. It reached the bottom 4.8 seconds later and hit the bottom of the cliff with a speed of 37 m/s. What total distance did it travel?"
I used these two equations (given y= distance, yi= initial distance, vi= initial velocity):
a. y=yi+vi(t)+1/2g(t^2)
b. v^2=vi^2+2a(y-yi)
And did not get the correct answer (which was 75 m). Can anybody give me the solution, or at the very least, a hint or correction? Thanks in advance.
P.S. I made sure that my calculations were correct in their mathematical nature.