Johan Abraham
New member
Here's the problem.
Say you have a resistance, a lamp or a motor, doesn't really matter. It has 50 ohms. You send through it 230 V. That gives you a current of I = U / R = 230 V / 50 ohms = 4.6 A
But, if I send it through a transformer that transforms it down to 23 Volts. That's 10 times lower than before, meaning the current is 10 times higher (given that P1 = P2). So why does not ohm's law apply? 230 V and 4.6 amperes, would give 23 V and 46 amperes.
I = U / R = 23 V / 50 ohms = 0.46 A
This is of course given that I'm sending it through the same resistance. What am I doing wrong? What am I missing? Please explain with calculations and what not.
The reason I'm so confused is that, if I have 12 V battery and transform it up 230 V, but without knowing that it has been transformed, I wouldn't know that its current would be a lot less than it be from an outlet. Or?
Sincerely,
Confused boy who's studying electricity.
Say you have a resistance, a lamp or a motor, doesn't really matter. It has 50 ohms. You send through it 230 V. That gives you a current of I = U / R = 230 V / 50 ohms = 4.6 A
But, if I send it through a transformer that transforms it down to 23 Volts. That's 10 times lower than before, meaning the current is 10 times higher (given that P1 = P2). So why does not ohm's law apply? 230 V and 4.6 amperes, would give 23 V and 46 amperes.
I = U / R = 23 V / 50 ohms = 0.46 A
This is of course given that I'm sending it through the same resistance. What am I doing wrong? What am I missing? Please explain with calculations and what not.
The reason I'm so confused is that, if I have 12 V battery and transform it up 230 V, but without knowing that it has been transformed, I wouldn't know that its current would be a lot less than it be from an outlet. Or?
Sincerely,
Confused boy who's studying electricity.