New math concept, please discuss...?

Define a new type a number system, whose unit is j, such that the absolute value of j, | j |, equals negative one (−1)

| j | = −1

(Im playing off the complex and imaginary numbers as a template for this theory)

Would such a number have meaning or use?
 
That sounds crazy. Let's see what happens!

Assume numbers in this new algebra have the form:
a + b*j
where a and b are real numbers.

In the algebra of complex numbers, the absolute value function computes the magnitude of the complex number, as if it were a vector:
|a + b*i| = sqrt(a^2 + b^2)

Since the absolute value function is nonlinear, it can't have distributivity. Therefore:
|a + b| â‰* |a| + |b|
I can't see a way to define |a + b*j| without using the definition from complex numbers.

However, we can throw out the real part and use only numbers of the form b*j.

If we look at numbers of the form b*i, then we could conceivably draw up this expansion of the absolute value function:
|2*i| = |2|*|i| = 2*1 = 2
|-2*i| = |2|*|-i| = 2*1 = 2
which would give us this general rule:
|b*i| = |b|

Being consistent, we should then apply this definition to your new number class:
|2*j| = |2|*|j| = 2*(-1) = -2
|-2*j| = |2|*|-j| = 2*(-1) = -2
which would give us this general rule:
|b*j| = -|b|

Note that here I decided to define |-j| = |j|, because |-b| = |b|, and I wanted to maintain this symmetry.

For some interesting reading, check out quaternions and the other hypercomplex algebras (octonions, sedenions).
 
OK

Just so we are clear, | j | = -1, not - j ??

So would this mean j^2 = 1??
What about sqrt j ? Does it = i or 1 ??
Is j + j = 2j and the does it equal 2?

Trying to understand if j is just the first number in the system or if it is really like the concept i.

If it is similar to i - then would the following be true??

i = i ++++ j = j
i^2 = -1 ++++ j^2 = 1
i^3 = -i ++++ j^3 = j
j^4 = 1 ++++ j^4 = 1

However,
| i | = i ++++ | j | = -1
| i^2 | = 1 ++++ | j^2 | = -1
| i^3 | = i ++++ | j^3 | = -1
| i^4 | = 1 ++++ | j^4 | = -1

Not sure about this - but this is my interpretation. Is that correct?

Sorry to answer a question with a question - but you did say to discuss.
 
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