Maths Mechanics Question - Friction and the Coefficient of Friciton :)?

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georgina

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Could someone please help, I have no idea on how to work-out this question. A case of mass 20kg lies on a rough horizontal floor under the action of a force P N - 20 degrees above the horizontal. The coefficient of friction between the case and the floor is 0.3. If the case is being moved at constant velocity, find the value of P. The value of P= 70.3N but how do you work this out? Thanks for all you help :)
 
Pcos20 = 0.3[(20g) + Psin20]
Solve for P,
P = 70.315 N
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Attention: g = 9.81 m/sec^2
 
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