Math online quiz need major help!!!?

M

Morgan

New member
Problem #1

Given:
log(x+4) - log(x)

Apply identity: log(a) - log(b) = log(a/b)
log((x+4)/x)




Problem #2

Given:
y^4/8(y^-4/8 + 5y^4/8)

Multiply terms:
y^0/64 + 5y^8/64

Simplify:
1/64 + 5y^8/64



Problem #3

Given:
(624x^4y)^(1/4) / (256xy^3)^(3/4)

Bring outer exponents down into expressions:
(624^(1/4) * x^1 * y^(1/4)) / (256^(3/4) * x^(3/4) * y^(9/4))

Combine exponents for "x" and "y":
(624^(1/4) * x^(1/4) ) / (256^(3/4) * y^2)

Evaluate 256^(3/4):
(624^(1/4) * x^(1/4) ) / (64 * y^2)

Since 624 doesn't have an integer quad-root, and since the
other part of the numerator *also* has an exponent of (1/4),
maybe it makes sense to combine them as follows:
(624x)^(1/4) / 64y^2


Arguably, you *could* collapse the constants to:
624^(1/4) / 64 = 0.078093731


.
 
1. Assume that x is a positive number. Use the logarithm properties to present the expression log (x+4)- log x as the logarithm of a single quantity.

2. Assume that all variables are positive and multiply.
y^4/8(y^-4/8 + 5y^4/8)

3. simplify the expression : (624x^4y)^1/4/(256xy^3)3/4 assume that all variables are positive numbers.
 
Back
Top