Last riddle for today, do you know the answer?

A professor tells her assistant that she dined with three people last night. She also tells him that the sum of the three people's ages is twice the secretary's own age and that the product of the three people's ages is 2,450. Then, she asks him to tell her the ages of the three people. After a while, the assistant tells the professor that he doesn't have enough information to solve the problem. She agrees and adds that she is older than all three people with whom she dined. The assistant, who knows her age, promptly gives the professor the correct ages. The question is: What are the ages of all five people in this story?
 
i cant be bothered to do all the math, but i THINK that the 3 people are all the same age, the professor is one year older than them, and the secretary is one year younger than them?

as a guess.
 
Consider all factorizations of 2450 into integers a, b, c. (Since
these three variables represent ages, all factors above 98 should
be excluded!) The remaining triples (a,b,c) sum to distinct values except 50+7+7 = 49+10+5 = 64. Since the assistant did not have enough information at this point, one of these two triples must be the
correct answer; in particular, the secretary's age is 64/2 = 32.
If the professor is 49 years old or younger, her assertion about
being older than all others at dinner cannot be true; if she is 51
or older, that information would not help the assistant. Hence,
the professor is 50, and her dinner guests had ages 49, 10, 5.
 
A chap on a long-haul flight, bored, asked the man next to him, "Riddle for you. Brothers and sisters have I none, but this man's father is this man's son. Who am I?" The chap scratches his head, but admits he has no idea. "It's me" he replies.
When matey gets off the plane he asks a mate."Brothers and sisters have I none, but this man's father is this man's son. Who am I?"
"It's you" replies his mate. "Wrong", he replies, "It's some fat gobby git I had to sit next to on the plane".
 
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