In labradors, black fur is dominant to yellow fur. Black pigment can only be

Diana

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produced if the gene for an? enzyme E is received, the absence of the enzyme automatically gives the dog yellow fur. Chocolate fur is the result of a dog being recessive for fur color, yet possesses at lease one copy of enzyme E. what would the phenotype ratio be in the cross of a heterozygous black labrador that is homozygous for enzyme E to a homozygous (pure-breeding) yellow labrador?
 
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