In Dallas the morning after a winter ice storm, a 1600-kg automobile going

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eastward on Chestnut Street at 40.0? Law of Conservation of momentum.
I dont know where to start besides that
In Dallas the morning after a winter ice storm, a 1600-kg automobile going eastward on Chestnut Street at 40.0 km/h collides with a 2800-kg truck that is going southward across Chestnut Street at 20.0 km/h. If the two vehicles become entangled and move together after the collision, what are the magnitude and direction of their velocity after colliding?
 
Total momentum before = Total momentum after.

P=mv
P(car) = 1600 x 11.11 m/s (convert km/h to m/s)
= 17777.77
P(truck) = 2800 x 5.55
= 15555.55

However using vectors you get a right angled triangle.
The value of the total momentum is sqareeroot (15555^2 + 17777^2)
= 23622

p=mv
23622 = (1600+2800) x V
velocity = 5.37 m/s in a south easterly direction
 
Total momentum before = Total momentum after.

P=mv
P(car) = 1600 x 11.11 m/s (convert km/h to m/s)
= 17777.77
P(truck) = 2800 x 5.55
= 15555.55

However using vectors you get a right angled triangle.
The value of the total momentum is sqareeroot (15555^2 + 17777^2)
= 23622

p=mv
23622 = (1600+2800) x V
velocity = 5.37 m/s in a south easterly direction
 
Total momentum before = Total momentum after.

P=mv
P(car) = 1600 x 11.11 m/s (convert km/h to m/s)
= 17777.77
P(truck) = 2800 x 5.55
= 15555.55

However using vectors you get a right angled triangle.
The value of the total momentum is sqareeroot (15555^2 + 17777^2)
= 23622

p=mv
23622 = (1600+2800) x V
velocity = 5.37 m/s in a south easterly direction
 
Total momentum before = Total momentum after.

P=mv
P(car) = 1600 x 11.11 m/s (convert km/h to m/s)
= 17777.77
P(truck) = 2800 x 5.55
= 15555.55

However using vectors you get a right angled triangle.
The value of the total momentum is sqareeroot (15555^2 + 17777^2)
= 23622

p=mv
23622 = (1600+2800) x V
velocity = 5.37 m/s in a south easterly direction
 
Total momentum before = Total momentum after.

P=mv
P(car) = 1600 x 11.11 m/s (convert km/h to m/s)
= 17777.77
P(truck) = 2800 x 5.55
= 15555.55

However using vectors you get a right angled triangle.
The value of the total momentum is sqareeroot (15555^2 + 17777^2)
= 23622

p=mv
23622 = (1600+2800) x V
velocity = 5.37 m/s in a south easterly direction
 
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