Im trying to work out how to get the equilibrium constant for a reaction from Ka

S

Samantha Pomeroy

New member
dissociation constants.? Given the following acid dissociation constants
Ka (HF) = 7.2 x 10^-4
ka (HCN) = 4.0 x 10^-10

determine the equilibrium constant for the reaction below
HCN (aq) + F (aq) ------> CN(aq) + HF (aq)
<-------
 
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