Question: an electron orbits a stationary proton at a distance of 5.29 x10^ -11. What is the kinetic energy of the electron?
Textbook answer: centripetal force =electric force.
mv^2 /r = QQ / (4pie Eo r^2)
Therefore 1/2 mv^2 = QQ/ (8pie Eo r)
Hnece K.E= -4.35 X 10^ -18 J
My question: How come gravitional force is not included since there is always a gravitonal force between two attractive particles orbiting each other. My take is that centripetal force = electric force + gravtional force. Is the textbook answer wrong OR is it because the mass of electron is too light and hence gravitional force is omitted?
Textbook answer: centripetal force =electric force.
mv^2 /r = QQ / (4pie Eo r^2)
Therefore 1/2 mv^2 = QQ/ (8pie Eo r)
Hnece K.E= -4.35 X 10^ -18 J
My question: How come gravitional force is not included since there is always a gravitonal force between two attractive particles orbiting each other. My take is that centripetal force = electric force + gravtional force. Is the textbook answer wrong OR is it because the mass of electron is too light and hence gravitional force is omitted?