H
hazelblue16
Guest
...to pass this class.? The owner of a pet store is trying to decide whether to discontinue selling specialty clothes for pets. She suspects that only 4% of the customers buy specialty clothes for their pets and thinks that she might be able to replace the clothes with more interesting and profitable items on the shelves. Before making a final decision she decides to keep track of the total number of customers for a day, and whether they purchase specialty clothes for their pet.
A. Assuming the pet store owner is correct in thinking that only 4% of her customers purchase specialty clothes for their pets, how many customers should she expect before someone buys a garment for their pet?
B. What is the probability that she does not sell a garment until the 7th customer? Show work.
C. What is the probability that exactly 3 out of the first 10 customers buy specialty clothes for their pet? Show work.
D. What is the probability that at least 4 out of the first 40 customers buy specialty clothes for their pet? Show work.
E. The owner had 275 customers that day. Assuming this was a typical day for his store, what would be the mean and standard deviation of the number of customers who buy specialty clothes for their pet each day?
F. Surprised by the high number of customers who purchased specialty pet clothing that day, the owner decided that her 4% estimate must have been too low. How many clothing sales would it have taken to convince you? Justify your answer.
A. Assuming the pet store owner is correct in thinking that only 4% of her customers purchase specialty clothes for their pets, how many customers should she expect before someone buys a garment for their pet?
B. What is the probability that she does not sell a garment until the 7th customer? Show work.
C. What is the probability that exactly 3 out of the first 10 customers buy specialty clothes for their pet? Show work.
D. What is the probability that at least 4 out of the first 40 customers buy specialty clothes for their pet? Show work.
E. The owner had 275 customers that day. Assuming this was a typical day for his store, what would be the mean and standard deviation of the number of customers who buy specialty clothes for their pet each day?
F. Surprised by the high number of customers who purchased specialty pet clothing that day, the owner decided that her 4% estimate must have been too low. How many clothing sales would it have taken to convince you? Justify your answer.