How to solve physics question?

A

angel

New member
A lift of mass 480kg is designed to carry a maximum load of 3000N. Calculate the tension in the lift cable at maximum load when:
a) the lift moves downward at a steady speed
b) the lift moves downward, acceleration at 1.5m/s^2
c) the lift moves downward, decelerating at 1.5 m/s^2
d) the lift moves upward, accelerating at 1.5 m/s^2
e) the lift moves upward, decelerating at 1.5 m/s^2

I need to use the F = ma equation only to solve these. please help! and can you please also explain it
shouldnt it be
b) F = M(g-a) , where a = 1.5m/s^2
c) F = M(g+a)
d) F = M(g+a)
e) F = M(g-a)
 
A load of 3000 N = 3000/g =306.12245kg
The total mass M = 480 + 306.12245 = 786.12245 kg
a) The tension in the cable = F = Mg
In the other cases 'a' has to be added to g with proper sign
b) F = M(g+a) , where a = 1.5m/s^2
c) F = M(g-a)
d) F = M(g-a)
e) F = M(g+a)
 
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