How to find the limiting Reactant? Chemistry problem.?

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2Al + 2KOH +6HOH ----> 2KAI(OH)4 + 3H2


Student uses the following quantities....

3.00 grams Al
15.0 mL of 8.00 M KOH
75.0 mL of distilled HOH

Which of these i the limiting reactant?
 
Refer to your periodic table to find the atomic masses of aluminium. Then convert grams to moles by the following formula

Grams/Atomic Mass=Number of moles

For solutions like KOH, take (Amount in mL/1000mL)*Molarity=Amount in moles

Distilled HOH is H20 is 100% water. 1mL of water is one gram.

Now time to go figure and compare it with the equation!
 
Refer to your periodic table to find the atomic masses of aluminium. Then convert grams to moles by the following formula

Grams/Atomic Mass=Number of moles

For solutions like KOH, take (Amount in mL/1000mL)*Molarity=Amount in moles

Distilled HOH is H20 is 100% water. 1mL of water is one gram.

Now time to go figure and compare it with the equation!
 
Refer to your periodic table to find the atomic masses of aluminium. Then convert grams to moles by the following formula

Grams/Atomic Mass=Number of moles

For solutions like KOH, take (Amount in mL/1000mL)*Molarity=Amount in moles

Distilled HOH is H20 is 100% water. 1mL of water is one gram.

Now time to go figure and compare it with the equation!
 
Refer to your periodic table to find the atomic masses of aluminium. Then convert grams to moles by the following formula

Grams/Atomic Mass=Number of moles

For solutions like KOH, take (Amount in mL/1000mL)*Molarity=Amount in moles

Distilled HOH is H20 is 100% water. 1mL of water is one gram.

Now time to go figure and compare it with the equation!
 
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