j_navratil
New member
How many grams of HgO react at the cathode of a mercury battery when 3.00 g of zinc is consumed at the anode?
HgO(s) + H2O(l) + 2e- --> Hg(l) + 2OH-(aq) Eo = 0.098 V
ZnO(s) + H2O(l) + 2e- --> Zn(l) + 2OH-(aq) Eo = -1.260 V
HgO(s) + H2O(l) + 2e- --> Hg(l) + 2OH-(aq) Eo = 0.098 V
ZnO(s) + H2O(l) + 2e- --> Zn(l) + 2OH-(aq) Eo = -1.260 V