The top of a volcano is viewed from a safe distance of 20,000 meters level to the base
of the volcano. The angle of inclination is found to be 22 degrees. If the angle of
incline from the base of the volcano to its summit is found to be 42 degrees, to the
nearest foot, how high is the volcano?
Here is a picture:
http://26.media.tumblr.com/tumblr_l1zh6027Ne1qa3wumo1_400.jpg
I have been trying so hard to do this haha. The answer is 14,658 meters, but I have no idea how to actually get it. So far I have tried tan 22= x/20,000 + y; x=(20,000+y)tan22; and tan42=x/y, so tan42=20,000+y/y. This has been unsuccessful hahaha.
We are not allowed to use Law of Sines, in case someone might find that advisable.
PLEASE HELP! I have an exam tomorrow
of the volcano. The angle of inclination is found to be 22 degrees. If the angle of
incline from the base of the volcano to its summit is found to be 42 degrees, to the
nearest foot, how high is the volcano?
Here is a picture:
http://26.media.tumblr.com/tumblr_l1zh6027Ne1qa3wumo1_400.jpg
I have been trying so hard to do this haha. The answer is 14,658 meters, but I have no idea how to actually get it. So far I have tried tan 22= x/20,000 + y; x=(20,000+y)tan22; and tan42=x/y, so tan42=20,000+y/y. This has been unsuccessful hahaha.
We are not allowed to use Law of Sines, in case someone might find that advisable.
PLEASE HELP! I have an exam tomorrow