How do I calculate the symmetrical angles of a polygon based on desired face count?

Halfingr

New member
I want to know how I can take a desired number, and make it into a polygon with that same amount of sides where all the faces are the same area/shape and all the angles are the same - like dice (d12/d20/etc.).

Maybe an equation where there are variables that represent the desired number of sides, and it gives an answer with angles that could be rendered in a 3 dimmensional space.

I know this is Geometrical Calculus kinda stuff, but I'm a dumbass in math, and only finished highschool with Algebra. =] But, to my knowledge, I think this would only work with whole, even numbers, right?
 
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