horrible pre-cal question! Please HELP! Thank you!?

  • Thread starter Thread starter A.J. T
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A.J. T

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H(t)= 1+.5(2t) I think? So really, H(t)= 1+t
you add 1 at the beginning because it's held 1m above ground. Since the angle is 30, the height is half the hypotenuse (length of the string) because a 30, 60, 90 triangle has sides of 1, 2, and sqrt(3). The length is 2t because distance=rate*time, where t=time and 2= the rate given of 2 m/s
 
A student holds a kite and a ball of string 1 meter above the ground and begins to let the string out at a rate of 2 m/s. If the string is at a 30 degree angle with the ground, express the height of the kite, H, as a function of time,T, in seconds arter it begins to fly.
 
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