T Tall Man Guest Oct 31, 2008 #1 If it takes 4.08 J of work to stretch a Hooke's-law spring 10.9 cm from its unstressed length, determine the extra work required to stretch it an additional 10.9 cm. Answer in J
If it takes 4.08 J of work to stretch a Hooke's-law spring 10.9 cm from its unstressed length, determine the extra work required to stretch it an additional 10.9 cm. Answer in J
S Super Fudge Guest Oct 31, 2008 #2 4.08 J (N*m)/(0.109m)^2 = K (spring constant in N/m) K*((0.109*2)^2) = work
