Help!!!!!!! grade 12 Math Review Questions!!!!!!?

  • Thread starter Thread starter Fabiha A
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Fabiha A

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I don't remember how do we do this:

Rationalize numerator:
1=> 3(√5) / 7+√2
2=> [(√x) - 3] / (x-9)
3=> [(√3+h)-(√3-h)] / h

rationalize denominator:
4=> [(2√5)+(3√2)] / [(2√5)-(3√2)]
5=> 4 / [(√x-2) - (√x)]
6=> x^2 / [(√x-1) - (√x+1)]

use exponent law to evaluate:
7=> [(2^-1)+(3^-2)] / (2^-3)

use exponent law to simplify:
8=> [(3x^2)^3] [(√x)^6]
9=> [(2/x)^n-r] [(x^2)^r]
10=> [(2x^4)^3] [(-4/x^5)^2]

simplify:
11=> (√96) - (√54) - (2√6)
12=> (2√40) - (√90) +(5√160)
13=> (√100X) - (√9X) + (√25X), where x>0
14=> [3√(9xy^4)] - [y√(16xy^2)]+[2y^2√(25x)], where x, y >0

solve for variable:
15=> m^3-m^2-17m+20=0
16=> (√3)sinx=cosx

find slope
17=> a horizontal line through (-3,4)
18=> a vertical line through (2,5)
19=> the line makes angle of 45 degrees with positive x-axis
20=> the line makes an angle of (3pii)/4 with positive x-axis

determine eqtn in standard form AxBy+C=0
21=> thru (2,-5) with slope m=3/4
22=> thru (1,-2) and parallel to 2x-3y+6=0
23=> thru (3,-4) and perpendicular to 5x+4y-7=0
24=> x-inter = 5, slope = 2/3
25=> x-inter = 2 and y-inter = 10

find the value of 'a' for each of following:
26=> (a,3) is a pt on the line 2x-y=0
27=> (a^2) - 3 and a-1 are the slopes of parallel lines
28=> a and (1-a) / 6 are slopes of perpendicular lines
29=> C(a,3) D(2,-1) and E(-3,4) and collinear points
30=> the line segment determind by (a,0) and (-3,-2) has slope -1/2
31=> the lines segments determined by X(5,4), Y(0,-1) and Z(a,3) from right angle triangle which is right - angled at Y

32 solve for system: 2x+ [(4y + 3) / 2]=2 [(3x+1) / 3] = y + 5/4

33. given f(x)=x^2 + 3x - 2 and g(x)=4x - 1, evaluate the following:
a.=> f (dot) g(x)
b.=> g (dot) f(x)
c.=> g[1/(x - 1)]
d.=> [f(x+h) - f(x)] / h
e.=> [g(2+h) - g(2)] / h
f.=> g^-1(x)
g.=> f(g^-1(x))

without calculator, find exact values of or simplify the following:
34=> if sec A= -5/4, find csc A tan A
35=> sin^2(pii/5) + cos^2(pii/5)
36=> 3sin2xcos2x
37=> 2cos^2(pii/4) - 1
38=> cos(pii/15)
 
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