Determine the solubility and solubility constant of PbCl2 (gmm=278.1). The dissolved Cl in the filtered solution was precipitated as AgCl by the addition of excess AgNO3 solution, dried and weighed. Here is my data:
Temp 20.2 degrees Celsius
Volume of PbCls solution analyzed, 25.00 mL
mass of dry AgCl 0.2543 g
equilibrium equation is PbCl2 <-> Pb2+ + 2Cl-.
CALCULATE:
Number of moles of:
1- AgCl-(s)
2- Cl-(aq)
3- Pb 2+ (aq)
4- [Cl-] in PbCl2 solution, M
5- [Pb2+] in PbCl2 solution , M
6- Ksp
7- Solubility of PbCl2, in g per 100 mL
Temp 20.2 degrees Celsius
Volume of PbCls solution analyzed, 25.00 mL
mass of dry AgCl 0.2543 g
equilibrium equation is PbCl2 <-> Pb2+ + 2Cl-.
CALCULATE:
Number of moles of:
1- AgCl-(s)
2- Cl-(aq)
3- Pb 2+ (aq)
4- [Cl-] in PbCl2 solution, M
5- [Pb2+] in PbCl2 solution , M
6- Ksp
7- Solubility of PbCl2, in g per 100 mL