Miller4Bears6
New member
region bounded by y = sqrt x and y = x, revolves around y axis.
intersection points (0,1) on x axis; vertical axis of revolution
Final answer pi(1/6) - 0 = .52359
did you get this too? just trying to catch my mistake.
shell method, not sure how to start. the distance from the solid to the origin p(x) is x?
set up: v = 2pi integral (x)(sqrt x)dx on (0,1) --> not sure if this is right.
thanks for everything
intersection points (0,1) on x axis; vertical axis of revolution
Final answer pi(1/6) - 0 = .52359
did you get this too? just trying to catch my mistake.
shell method, not sure how to start. the distance from the solid to the origin p(x) is x?
set up: v = 2pi integral (x)(sqrt x)dx on (0,1) --> not sure if this is right.
thanks for everything