Find the original dimensions of the garden?

Derek

New member
Homework question, not sure what to do on it:

A rectangular garden is 4ft longer than it is wide. If the width is decreased by 1 ft., and the length is increased by 5ft., the area is increased by 15 square ft. Find the original dimensions of the garden.
 
Let A be the area, L be the length and W be the width

"A rectangular garden is 4ft longer than it is wide" tells us L = W + 4

Also area = length x width, so A = LW,

"If the width is decreased by 1 ft., and the length is increased by 5ft., the area is increased by 15 square ft" tells us (W-1)(L+5) = A + 15.

Expanding out the brackets on the left hand side gives LW + 5W - L - 5 = A + 15. Since A = LW, this can be written as A + 5W - L - 5 = A + 15, and subtracting the A from both sides and adding 5 to both sides tells us 5W - L = 20 and substituting in L = W + 4 tells us 5W - (W + 4) = 20, which is the same as 5W - W - 4 = 20, which simplifies to 4W = 24 and therefore W = 6. Also L = W + 4 = 6 + 4 = 10.

So the garden is 6 feet wide and 10 feet long.
 
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