I have the correct answer, but I am not sure how to get there. Here is what I get when setting it up in a table...
f(x)=e^(3x) f(a)=0
f'(x)=3x^(3x) f'(a)=3
f''(x)=9x^(3x) f''(a)=9
f'''(x)=27x^(3x) f'''(a)=27
That is all I have so far. I am not really sure if that is even correct. Could someone dumb it down as much as possible? I don't even really understand the way the book puts it with all its Calculus lingo.
The correct answer is 1+3x+(9/2)x^2+(9/2)x^3
f(x)=e^(3x) f(a)=0
f'(x)=3x^(3x) f'(a)=3
f''(x)=9x^(3x) f''(a)=9
f'''(x)=27x^(3x) f'''(a)=27
That is all I have so far. I am not really sure if that is even correct. Could someone dumb it down as much as possible? I don't even really understand the way the book puts it with all its Calculus lingo.
The correct answer is 1+3x+(9/2)x^2+(9/2)x^3